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0.0075x^2+0.5x+5=0
a = 0.0075; b = 0.5; c = +5;
Δ = b2-4ac
Δ = 0.52-4·0.0075·5
Δ = 0.1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{0.1}}{2*0.0075}=\frac{-0.5-\sqrt{0.1}}{0.015} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{0.1}}{2*0.0075}=\frac{-0.5+\sqrt{0.1}}{0.015} $
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